- #1
Breston
- 9
- 0
Hi there, right now I am making my first steps towards physics, and I would appreciate your help to solve some of my problems. As you surely have already noticed, I'm not english and I guarantee I'll make thousands of errors. Should I make any, please, try to always advise me, and if it's not too annoying, a correction would be neat.
Two identical poles of length L and mass M are secured at one extremity they ave in common, so that they move and rotate integrally and they make an angle of [itex]\frac{\pi}{2}[/itex].
At the beginning, they are located so that the common vertex is at the origin, the poles are oriented along the positive x and y-axis and they may only rotate over the origin (around the Z axis).
A particle of mass m and initial velocity [itex]\vec{v_i} = 2.3\ \hat{x}\ \frac{m}{s}[/itex]
is directed toward the free extremity of the pole along the y axis. After the collision, its velocity is [itex]\vec{v_f} = 0.7\ \hat{x}\ \frac{m}{s}[/itex].
Friction does not exist (or at least not in this problem ;) )
Calculate the angular velocity [itex]\omega[/itex] of the poles after the collision and the mechanic energy dissipated during the collision.
[itex]M = 0.45 kg[/itex]
[itex]L=0.30 m[/itex]
[itex]m=0.12 kg[/itex]
Energy conservation..
From kinetic energy conservation I think this should be enough to resolve:
[itex]\frac{1}{2}mv_i^2 = \frac{1}{2}mv_f^2+\frac{1}{2}I_{O}\omega^2[/itex]
with no energy dissipated during the collision.
Of course I'm wrong and there IS energy dispersion, though I have no idea how to account of it..
Homework Statement
Two identical poles of length L and mass M are secured at one extremity they ave in common, so that they move and rotate integrally and they make an angle of [itex]\frac{\pi}{2}[/itex].
At the beginning, they are located so that the common vertex is at the origin, the poles are oriented along the positive x and y-axis and they may only rotate over the origin (around the Z axis).
A particle of mass m and initial velocity [itex]\vec{v_i} = 2.3\ \hat{x}\ \frac{m}{s}[/itex]
is directed toward the free extremity of the pole along the y axis. After the collision, its velocity is [itex]\vec{v_f} = 0.7\ \hat{x}\ \frac{m}{s}[/itex].
Friction does not exist (or at least not in this problem ;) )
Calculate the angular velocity [itex]\omega[/itex] of the poles after the collision and the mechanic energy dissipated during the collision.
[itex]M = 0.45 kg[/itex]
[itex]L=0.30 m[/itex]
[itex]m=0.12 kg[/itex]
Homework Equations
Energy conservation..
The Attempt at a Solution
From kinetic energy conservation I think this should be enough to resolve:
[itex]\frac{1}{2}mv_i^2 = \frac{1}{2}mv_f^2+\frac{1}{2}I_{O}\omega^2[/itex]
with no energy dissipated during the collision.
Of course I'm wrong and there IS energy dispersion, though I have no idea how to account of it..