Calculating Coefficient of Friction: Newton's 3rd Law Examples

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To calculate the coefficient of kinetic friction for the 50kg block being pulled with a force of 120N, the frictional force equals the applied force since the block moves at a constant speed, leading to a coefficient of 0.24. For the 100kg wooden crate pushed with a force of 350N, the net force is determined by subtracting the frictional force from the applied force, which requires the coefficient of friction for further analysis. In the case of the 400N cabinet being pulled at a constant speed with a 220N force at a 30-degree angle, the vertical component of the force reduces the normal force, allowing for the calculation of the coefficient of sliding friction. The solving strategy involves applying Newton's laws, particularly focusing on the balance of forces and the relationship between friction and normal force. Understanding these principles is crucial for accurately determining coefficients of friction in various scenarios.
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1.) a 50kg block is being pulled at a constant speed along a horizontal surface by a horizontal force of 120N.

Q: what is the coefficient of kenetic friction?

2.) a 100kg wooden crate is being pushed across a wooden floor with a horizontal force of 350N.
Q: What is the net force acting on a crate?

3.) A cabinet weighing 400N is pulled along a horizontal floor at constant speed by a rope which makes an angle of 30 degrees with the floor.

Q: what is the coefficient of sliding friction if the force on the rope is 220N?



Thanks in advance...
 
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Could you show what solving strategy you have applied here?
 

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