Engineering Calculating Current in Thevenin Equivalent Circuit?

AI Thread Summary
To calculate the current in a Thevenin equivalent circuit, first determine the Thevenin resistance (Rth) by deactivating all sources and measuring the resistance between points A and B. Kirchhoff's Current Law (KCL) can be applied at the node with the -8.7V voltage to find the short-circuit current (Isc). The node voltages of -6.7V and -8.7V are relevant for calculating Isc, and the 1mA source should be considered in parallel with a short circuit. When applying KCL at node A, the correct equation is IR10 = Isource + I, ensuring the current directions are properly accounted for. Understanding these principles will facilitate accurate calculations in complex circuits.
john88
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I trying to figure out a thevenin equivalent circuit

I want to calculate the current I so I can't get the resistance for the thevenin equivalent.

Im not 100% sure how to calculate I, can I use KCL on the node under the number -8.7V?

http://img98.imageshack.us/my.php?image=curfc7.jpg
 
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That sure is a complex circuit. To find Rth, kill all the current and voltage sources and then measure the equivalent resistance between A&B.

KCL is valid everywhere. Is that -6.7 and -8.7 node voltages given by the question? If so, then you can easily find Isc. Also note that the 1mA source is connected in parallel with a short-circuited wire.
 


so if short circuit the system. Can I setup KCL on node A and then solve for I,
I = I(source) + I(R10).

But it seems odd to do so.
 


You got the equation wrong. It's IR10 = Isource + I. Be careful of the direction designated for Isc.
 


ok, got everything together now, ty for the help!
 

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