Calculating Energy Dissipation in Free Fall with Drag Force

AI Thread Summary
The discussion focuses on calculating energy dissipation due to drag force on a ball in free fall, specifically when it reaches terminal velocity before hitting the ground. The drag force is defined as bv^2, with b being the drag coefficient and v the instantaneous speed. The terminal velocity is calculated as Vt = √(mg/b), and energy dissipation is initially considered as Ediss = mgh. However, there is confusion regarding the relationship between energy dissipation and height, as the terminal velocity equation does not include height. The conversation concludes that the problem is solvable by applying the equation mv' = -bv^2 + mg.
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Homework Statement


Need to energy dissipation by the drap force on a ball in free fall from height h and when it has reached terminal speed, assuming it happens before it hits thr ground. Drag force has magnitude bv^2, where b is drag coefficient and v is instantaneous speed of the ball.


Homework Equations



I have calculated in an earlier part of the problem that terminal velocity:
Vt=root(mg/b)

Also, isn't the energy dissipation equation:
Ediss=mgh

The Attempt at a Solution



I have the above equations but am unclear where to move next.
 
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Not sure what you mean by Ediss=mgh. If chosing conservation of energy, one could simply assume that the drag energy(work) is the difference between the final and initial sums of PE and KE. The problem I see, is that the eqn you posted for Vt says nothing about height.

In other words if we knew the distance required to reach terminal velocity, you're home free.
 
Ok will check that, Ediss is Energy dissipated

thx!
 
no sweat, either way problem is soluble:

mv'=-b*v^2+mg.
 
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