Calculating Force Needed to Distort Steel Plate

AI Thread Summary
To calculate the force needed to distort a steel plate measuring 10 cm square and 0.25 cm thick by 0.04 cm, the shear modulus of steel, which is 80 x 10^9 N/m^2, is essential. The relationship between stress, strain, and shear modulus is highlighted, where stress is defined as force divided by area and strain as the change in length divided by the original length. The equation F/A = G * (Delta H/H) is confirmed as valid for this calculation. By applying these principles, one can derive the necessary force to achieve the specified distortion. Understanding these mechanical properties is crucial for accurate calculations in material science.
samemikejones
Messages
5
Reaction score
0
A steel plate of 10 cm square or (100 sq cm) is .25cm thick. How much force is need to distort its edges by 0.04 cm.
sheer modulus for steel is 80 * 10^9 n/m^2,


Plz Help Thanx
 
Last edited:
Physics news on Phys.org
Remember that the sheer (or shear) modulus is given by stress divided by strain.

Where Stress is Force/Area.

And Strain is the Change in Length / Original Length.

This should be enough to get you going.
 
Not sure if that equation is right, because they give you the shear modulus in the question, so I found an equation with G in it, F/A = G * Delta H/H, the other equation does not have G in it
 
If G is the shear modulus, then the equation that you have written:

F/A = G * Delta H/H,

is exactly the same as what I wrote in my last post.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top