Calculating Moles of Chlorine Atoms in 71g of MCl2

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SUMMARY

The discussion focuses on calculating the number of moles of chlorine atoms in 71 grams of MCl2, where MCl2 has a molar mass of 70.9 g/mol. The solution involves recognizing that each molecule of MCl2 contains two chlorine atoms. Therefore, using the formula for moles, the calculation confirms that 71 g of MCl2 corresponds to 1.00 mol of MCl2, resulting in 2.00 moles of chlorine atoms. The atomic weight of chlorine is approximately 35.5 g/mol, which supports this calculation.

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Homework Statement


How many moles of chlorine atoms are there in 71g?

Given:
mCl2=71g
nCl2=1.00 mol
MCl2=70.9g/mol

Homework Equations



?

3. The Attempt at a Solution

Not sure how to go about this question.

Would it just be n multiplied by 2?
 
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Sace Ver said:

Homework Statement


How many moles of chlorine atoms are there in 71g?

Given:
mCl2=71g
nCl2=1.00 mol
MCl2=70.9g/mol

Homework Equations



?

3. The Attempt at a Solution

Not sure how to go about this question.

Would it just be n multiplied by 2?
Yes. The question asks for how many moles of chlorine atoms there are in 71 g. The atomic weight of one chlorine atom is approx. 35.5

https://en.wikipedia.org/wiki/Chlorine
 

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