Calculating Net Heat Flow for an Aluminum Disk in a Room

AI Thread Summary
The discussion centers on calculating the net heat flow of an aluminum disk with low emissivity placed in a room. The formula used is Hnet = A*e*σ(Tradiate^4 - Tabsorb^4), and the calculated value is 0.13 W, which does not match the provided answer choices. Participants suggest that the discrepancy may be due to a negative sign or a potential mistake in the coursework. It is noted that the answer choices differ by a factor of around √2, indicating a possible error in the problem setup. The final consensus is that the calculated value of 0.13 W is likely correct, pending clarification on the direction of heat flow.
lonelypancreas
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Homework Statement


What is the net heat flow of an aluminum disk (emissivity = 0.05) with radius
10 cm and temperature 293K placed inside a room where the temperature is 300K?


Asurface = π*r2 = 0.01π m2

Homework Equations


Hnet = A*e*σ(Tradiate4-Tabsorb4)

The Attempt at a Solution


By simply plugging in the values, I get a value of 0.13. However, the answer is not among the choices.

Where did I possibly go wrong?
 
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lonelypancreas said:

Homework Statement


What is the net heat flow of an aluminum disk (emissivity = 0.05) with radius
10 cm and temperature 293K placed inside a room where the temperature is 300K?


Asurface = π*r2 = 0.01π m2

Homework Equations


Hnet = A*e*σ(Tradiate4-Tabsorb4)

The Attempt at a Solution


By simply plugging in the values, I get a value of 0.13. However, the answer is not among the choices.

Where did I possibly go wrong?
That's the numerical answer that I got (don't forget to include your units in the future), with the possible exception of a negative sign.

What are the other choices?
 
collinsmark said:
That's the numerical answer that I got (don't forget to include your units in the future), with the possible exception of a negative sign.

What are the other choices?

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lonelypancreas said:
Hmm. The given answer choices differ from our answer by a factor of around √2, for what that's worth.

Unless there's more to the problem though I think our answer of 0.13 W is correct*. I don't know, maybe it's a mistake in the book/coursework?

*I'll let you figure out if it's into or out of the disk.
 
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