Calculating normal force in a loop-the-loop situation

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SUMMARY

The discussion focuses on calculating the normal forces exerted on a pilot during a vertical loop-the-loop maneuver in an aircraft traveling at a speed of 700 km/h (194.444 m/s) with a loop radius of 2.0 km (2000 m). The calculated normal force at the bottom of the loop is 2.93 times the pilot's weight (mg), while at the top, it is 0.929 times mg. The key equations involved include centripetal force (F = mv²/r) and gravitational force (F = mg), with emphasis on free-body diagrams to analyze forces at different points in the loop.

PREREQUISITES
  • Understanding of centripetal force and its calculation (F = mv²/r)
  • Knowledge of gravitational force and its impact on objects (F = mg)
  • Ability to create and interpret free-body diagrams
  • Familiarity with angular motion concepts, including angular velocity and acceleration
NEXT STEPS
  • Study the derivation and application of centripetal force equations in circular motion
  • Learn how to construct and analyze free-body diagrams for dynamic systems
  • Explore the effects of varying speeds on normal forces in circular motion scenarios
  • Investigate the relationship between angular velocity and centripetal acceleration
USEFUL FOR

Physics students, aerospace engineers, and anyone interested in understanding forces in circular motion, particularly in aviation contexts.

jeanjacket
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Homework Statement



Here's the situation:

A jet pilot puts an aircraft with a constant speed into a vertical circular loop. If the speed of the aircraft is 700 km/h and the radius of the circle is 2.0 km, calculate the normal forces exerted on the seat by the pilot at the bottom and top of the loop. Express your answer in terms of the pilot's weight mg.

a) at the bottom
b) at the top

I actually have the answers to the problem, but of course it doesn't help me understand the problem nor the process in getting there. Not sure which angular motion/centripetal force equations to use. But if it helps you verify results, here are the answers:

At bottom: 2.93*mg
At the top: .929*mg

I would really appreciate any help, even if it's just pointing me in the right direction as far as which equation to use, I'm not necessarily asking anyone to work it out. Thanks in advance!

Homework Equations



Not necessarily sure which to use, here's some conversions just for quick reference:
700 km/h = 194.444 m/s
2.0 km = 2000 m

Possible eqns:

Angular Velocity = \omega = \Delta\theta/\Deltat
Angular Acceleration = \alpha = \Delta\omega/\Deltat
\textbf{F}_{centripetal} = mass x accel(centrip) = mv^{2}/r
\textbf{F}_{gravity} = mg

The Attempt at a Solution



Can't quite figure out where to start...
 
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Start with 2 free-body diagrams, 1 for the forces on the pilot at the top of the loop and one for the bottom. Keep in mind what force(s) provide the centripetal acceleration for the pilot at those points.
 
At all times the centrifugal acceleration pushes the pilot onto the seat. The difference is the direction of the weight of the pilot, which is always the directed towards the centre of the earth. So at the bottom force = centrifugal + weight, at top its centrifugal - weight.
 

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