Calculating Time Until Voltage Falls in a Circuit with Resistor and Capacitor

AI Thread Summary
To calculate the time until the voltage across a capacitor falls to a specific fraction of its initial value, the time constant (T) is determined using the formula T = cR, where c is the capacitance and R is the resistance. For a capacitor of 35 microfarads and a resistor of 120 ohms, the time constant can be calculated, and the voltage decay can be expressed using V(final) = V(initial) e^(-t/CR). Logarithms may be necessary to solve for time when setting the voltage to the desired fraction. Additionally, in a circuit with an uncharged capacitor and a bulb, the bulb will initially remain off, then gradually light up as the capacitor charges, becoming brighter over time. This behavior is consistent with the charging process of a capacitor in a series circuit.
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If a charged capacitor c=35 micro farads is connected to a resistor R=120 ohms how much time will elapse until the voltage falls to 10^6/D of its original max value?

Ciruit contains a switch, resistor, emf and a capacitor in series.

Relevant equations are Time constant= T=cR and V(Final)=V(initial) e^-t/cr


I think it requires logarithms but i am not sure.

Can you please help me how to answer this.
 
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Another question is:

A circuit containing a switch, Vo, a capacitor and a bulb in series.

The capacior is originally uncharged. Describe the behaviour of the bulb from the instant the switch is on until a long time later.

I think there will be a delay for the bulb to emit light and then it will emit light getting slowly brighter as the capacitor is getting charged up.

Is this right?
 
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