Calculating Volume for 1 kg of O2 at 150,000 Pa and 100K using Ideal Gas Law

AI Thread Summary
To calculate the volume of 1 kg of diatomic oxygen at 150,000 Pa and 100K using the Ideal Gas Law, the correct number of moles (n) must be determined by converting the mass to grams, resulting in 31.25 moles. The Ideal Gas Law equation, PV = nRT, can then be rearranged to find volume (V = nRT/P). The appropriate gas constant (R) for the calculations should be used, and unit conversions must be checked for accuracy. The discussion highlights the importance of correctly interpreting mass and moles in gas calculations.
Rockstar47
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Homework Statement



I need to find the volume for 1 kg of diatomic oxygen for a pressure of 150,000 Pa and a temperature of 100K. This is really part of a larger project, and I need to make sure I'm not tripping up on little details. It's that 1 kg of diatomic oxygen that I am a bit unsure about, or just plain having a brain freeze about.

R* = 8.314 J/K*mol
T = 100 K
P = 150,000 Pa
n = ??

Homework Equations



PV = nRT

The Attempt at a Solution



Solving the equation for V; V = nRT/P. No big deal. My problem is making sure I have the correct n in the equation. The mass of diatomic oxygen is 32.0 grams, which is what I was using in my solutions. However, I realize that I have 1 kg of O2, not 1 g of it. Should I really be using 32,000 for my n? Or something else?
 
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you're using the wrong R constant. I'm working on it right now.
 
Last edited:
You haven't properly converted mass to moles. Check that your units make sense in your calculation.
 
Thanks, everyone.

If I am looking at this all correctly, since I have 1 kg of diatomic oxygen, my number of moles should be: 1000 g / 32.00 g, which gives me my number of moles (n) equal to 31.25. Am I on the right track now?
 
yeppp
 
Thanks for the help, everyone! It was a total brain freeze on my part...
 
Rockstar47 said:
Thanks for the help, everyone! It was a total brain freeze on my part...
what was your final answer?
 
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