Calculating Work for Climbing Stairs

  • Thread starter Thread starter jsr219
  • Start date Start date
  • Tags Tags
    Work
AI Thread Summary
A 75-kg person climbing a flight of stairs 10 m high does approximately 7357.5 joules of work, calculated using the formula W = (f)(d), where force is derived from the person's weight. The force is determined by multiplying mass (75 kg) by gravity (9.81 m/s²), resulting in 735.75 N. This force is then multiplied by the distance (10 m) to find the total work done. The correct answer is approximately 7350 J, confirming the calculations are accurate. Understanding that work is the product of force and distance is crucial in these physics problems.
jsr219
Messages
8
Reaction score
0
How much work is done when a 75-kg person climbs a flight of stairs 10 m high at a constant speed

A.) 7.35 * 10^5 j
B.) 750 j
c.) 75 j
D.) 7500 j
E.) 7350 J


W = (f)(d)
f = ma
W= (ma)(d)



Now I'm assuming that the force is parallel to the stairs (distance as the person walks up the stairs)

so I found the force
f = ma
f= (75)(9.81) = 735.75


then I solved for work
W = (f)(d)
W = 735.75(10)
W = 7357.5 j

answer E

I'm new to to work so I just want to clarify if I'm doing the problem right or wrong
If I made any errors please feel free to correct me
We learn by our mistakes after all

Thank You
 
Physics news on Phys.org
Your answer is correct. Work is just force acting over a distance. Here, the force is the weight of the person (force of gravity), and the distance is the height of the steps.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top