Engineering Capacitor charge time on DC RLC circuit

AI Thread Summary
In a DC RLC circuit with a 220 V source, a 10 F capacitor, a 5 H inductor, and a 22-ohm resistor, the discussion focuses on determining the charge time of the capacitor. The initial voltage across the capacitor is 50 V, and it is noted that the capacitor behaves like a short circuit until fully charged, after which it acts as an open circuit. The user attempted to apply Kirchhoff's Voltage Law (KVL) and derived a differential equation for the capacitor voltage (Vc) but encountered difficulties in progressing further. Clarification is sought regarding the specific equation used in the analysis. The conversation emphasizes the importance of understanding the charging behavior of capacitors in RLC circuits.
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Homework Statement



Inductor, resistor and a capacitor is connected to a DC source in series.
DC source is 220 V
Capacitance is 10F
Inductance 5H
Resistor 22 ohm
Vc(0) = 50V

Question is asking for the charge time of the capacitor, when it gets charged fully and then it starts to act like open circuit (If I'm not mistaken it must be act like short until gets fully charged and then acts like open circuit)

Homework Equations





The Attempt at a Solution



I wrote down the KVL and equation. And then replaced the VL with L.dI/dt and I=C.dVc/dt
Finally I ended up with a dif. equation on Vc.

However, I couldn't proceed any further.
 
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zoom1 said:


The Attempt at a Solution



I wrote down the KVL and equation. And then replaced the VL with L.dI/dt and I=C.dVc/dt
Finally I ended up with a dif. equation on Vc.

However, I couldn't proceed any further.


Why not? What was your equation?
 

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