Carnot Heat Engine to Carnot Heat Pump

AI Thread Summary
The discussion centers on the relationship between a Carnot heat engine and a Carnot heat pump, specifically regarding the heat absorbed by each system. The Carnot engine operates with a high temperature of 800 degrees Celsius and a low temperature of 50 degrees Celsius, while the heat pump has reservoirs at 50 degrees Celsius and 0 degrees Celsius. The ratio of heat absorbed by the heat engine to that of the heat pump was initially thought to be infinite due to a division by zero when applying the same temperature ratio method. However, it was pointed out that the wrong temperature scale was being used, which led to confusion. This realization highlights the importance of using the correct temperature scale in thermodynamic calculations.
keith river
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We have a carnot engine with Th = 800 degrees Celsius, and Tc = 50 degrees Celsius.
This produces a work which is drives a carnot heat pump which has heat reservoirs at Th' = 50 degrees celsius and Tc' = 0 degress Celsius.
What is the ratio of heat absorbed by the Heat Engine to the heat absorbed by the heat pump.

I know the ratio from Qh/Qc for the heat engine would be Th/Tc but when I was planning on doing the same for a heat pump (Qh'/Qc') but It doesn't work out as the ratio would be infinite (divides by 0)
I was going to rearrange for Qh/Qc' as these are the heats absorbed by the heat engine and pump respectfully but this also would be infinite.
 
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keith river said:
We have a carnot engine with Th = 800 degrees Celsius, and Tc = 50 degrees Celsius.
This produces a work which is drives a carnot heat pump which has heat reservoirs at Th' = 50 degrees celsius and Tc' = 0 degress Celsius.
What is the ratio of heat absorbed by the Heat Engine to the heat absorbed by the heat pump.

I know the ratio from Qh/Qc for the heat engine would be Th/Tc but when I was planning on doing the same for a heat pump (Qh'/Qc') but It doesn't work out as the ratio would be infinite (divides by 0)
I was going to rearrange for Qh/Qc' as these are the heats absorbed by the heat engine and pump respectfully but this also would be infinite.
You are using the wrong scale for temperature.

AM
 
Thanks AM
I can't believe I never noticed that before. Such a simple problem.
 
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