How Do You Apply the Chain Rule to Differentiate f(x) = x^5(4^(x^2))?

ninanana
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I'm so confused. I have to find the derivative of f(x) = x^5(4^(x^2)). All of the powers are messing me up. Any help would be much appreciated. Thanks!
 
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Is your function f(x) = x^5(4^{x^2}) or f(x) = x^{5(4^{x^2})} ?
 
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The first one, sorry.
 
Use product rule first, then you end up differentiating 4^(x^2).
A nice formula to know is d/dx ( a^(f(x)) ) = a^f(x) * ln(a) * f'(x), which comes from the chain rule.
 
I know I'm having some sort of stupid lapse right now, but the part I can't figure out is the 4^(x^2).
 
To differentiate y= 4^{x^2}, take the logarithm of both sides:
ln y= x^2 ln 4
Now differentiate that, with respect to x.
\frac{1}{y}y'= 2x ln 4
so
y'= 2x (ln 4)y= 2x 4^{x^2} ln 4

Karlsen used the fact that the derivative of ax is ax ln a, but not everyone knows that!
 
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