- #1
TTauri
- 4
- 1
- Homework Statement
- In a certain region of space, there is a uniform electric field of magnitude
10.0 V m−1 directed at 45.0◦ to the positive direction of both the x and y axes. (There is no z
component of the electric field.) The electric potential at the origin is +100 V. What is the electric
potential at the point where x = 4.00 m and y = 3.00 m?
- Relevant Equations
- Ex = -dV/dx
Ex =10.0Vm-1
dx= d2=x2+y2
x=4.00m
y=3.00m
d2=4.002+3.002
d=5.00m
Ex = -dV/dx
10.0Vm-1=-dV/5.00m
10.0Vm-1*5.00m=-dV
-50.0V=dV
So from origin at 100V-50.0V = 50.0V
But the solution I am given gives the answer at 50.5V and the information "directed at 45.0◦ " does not seem to have been used so may related to the difference.
I have hunted a bit round the internet and through textbooks but cannot find this formulation with the field being directed at an angle.
dx= d2=x2+y2
x=4.00m
y=3.00m
d2=4.002+3.002
d=5.00m
Ex = -dV/dx
10.0Vm-1=-dV/5.00m
10.0Vm-1*5.00m=-dV
-50.0V=dV
So from origin at 100V-50.0V = 50.0V
But the solution I am given gives the answer at 50.5V and the information "directed at 45.0◦ " does not seem to have been used so may related to the difference.
I have hunted a bit round the internet and through textbooks but cannot find this formulation with the field being directed at an angle.
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