What is the Pressure Change in a Pipe for Salt Water Transport?

AI Thread Summary
The discussion focuses on calculating the pressure change in a pipe transporting salt water to a desalination plant. Given an initial pressure of 80 kPa at a depth of 1.00 m, the pressure at a height of 5.00 m is determined using the hydrostatic pressure equation. The calculations reveal that the pressure decreases to approximately 19,400 Pa after accounting for the height difference and the density of salt water. Participants emphasize the importance of significant figures in reporting the final answer. The final pressure value is confirmed as accurate.
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Homework Statement


A pipe has a square cross section and a width of 2.00 m and is used to transport salt water from the ocean into a desalination plant. If a pump pushing the water into the pipe at a depth of 1.00 m below the surface of the ocean does so with a pressure of 80 kP a, and the dimensions of the pipe doesn’t change, what is the pressure in the pipe when it gets into the plant at a height of 5.00 m above the surface of the ocean?

Homework Equations


A*v=A*v
P1+1/2p*v^2 + pgy = P2 + 1/2p*v^2 + pgy
P_2 = P_1 + p*g*(y_1 - y_2)[/B]
p_saltwater = 1030 kg/m^3

The Attempt at a Solution


P_2 = P_1 - p*g*(4)
= 80000 + (1030)(9.81)(4) = 39582.8 [/B]
 
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mailmas said:
P_2 = P_1 - p*g*(4)
4? Read the question more carefully.
 
haruspex said:
4? Read the question more carefully.
80000 - (1030)(9.81)(6) = 80000 - 60625.8 = 19374.2
 
mailmas said:
80000 - (1030)(9.81)(6) = 80000 - 60625.8 = 19374.2
Looks better, but you quote too many significant figures.
 
haruspex said:
Looks better, but you quote too many significant figures.
19400 Pa
 
mailmas said:
19400 Pa
Looks fine.
 
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