Using Cauchy's Tip for Changing Integral Variable Inconsistencies

baby_1
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Homework Statement


I want to change integral variable to jx it means (w=jx)
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Homework Equations

The Attempt at a Solution


3381303200_1470901807.jpg

but as you see the bounds of integral are different from the book text , what is my mistake?
 
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hat about the part that says: "by using the Cauchy theorem and showing that..."?
 
dear Simon
I didn't understand how can I use the Cauchy tip to solve this inconsistency?
 
It's a step you seemto have left out though.
I'll agree it looks like there's a minus sign missing. Maybe there's a typo? I can't actually read the image properly.
 
baby_1 said:
dear Simon
I didn't understand how can I use the Cauchy tip to solve this inconsistency?

It allows you to perform the integral from \omega = -i\infty to \omega = +i\infty, which on setting \omega = ix becomes x = -\infty to x = \infty.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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