Charge on 4 capacitors in parallel then series

AI Thread Summary
When switch S is closed, the charge on capacitors C1 and C2 is 8μC, while C3 and C4 each hold 6μC due to their series configuration. The equivalent capacitance for the parallel groups C1 and C3 is 4μF, and for C2 and C4, it is 6μF. The total voltage of 12V will divide across the series combination of these two groups. Understanding the voltage distribution and charge behavior in both series and parallel configurations is crucial for solving the problem.
neshepard
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Homework Statement



C. What is the charge on each of the four capacitors if switch S is closed? I have the charges if the switch is open, C1 and C2 are 8μC and C3 and C4 are 6μC since charges are same on series.

Homework Equations





The Attempt at a Solution



I know to find Ceq and work backwards, and that voltage in parallel is the same. But what happens to the volatage's and charges in both a series and parallel layout?
C1 and C3 are parallel Ceq=4μF
C2 and C4 are parallel Ceq=6μF
Each parallel group is in series.
 
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A diagram would go a long way to making the question clear.
 
Trying to figure how to add on.
 

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neshepard said:
I know to find Ceq and work backwards, and that voltage in parallel is the same. But what happens to the volatage's and charges in both a series and parallel layout?
C1 and C3 are parallel Ceq=4μF
C2 and C4 are parallel Ceq=6μF
Each parallel group is in series.

Call C1 in parallel with C3 "C13". Similarly "C24" is C2 in parallel with C4.
Now, C13 = 4μF and C24 = 6μF, as you've calculated above.

The first thing to do is determine how the 12V supply voltage will divide over the series combination of C13 and C24.
 
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