Charge on a point in three different locations with a thin semicircular rod

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    Charge Point Rod
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Homework Help Overview

The discussion revolves around the electric forces acting on a positive test charge placed at three different points (A, B, C) in relation to a thin semicircular rod with a uniform charge distribution of +Q on the top half and -Q on the bottom half.

Discussion Character

  • Conceptual clarification, Assumption checking, Exploratory

Approaches and Questions Raised

  • Participants explore the direction of the net electric force on the test charge at points A, B, and C, considering both horizontal and vertical components of the forces from the charged rod.

Discussion Status

There is an ongoing exploration of the resultant force direction, with some participants suggesting that the horizontal components cancel each other out, leading to a vertical force direction. The discussion reflects varying interpretations of the resultant force at different points.

Contextual Notes

Participants are considering the effects of distance from the charge distribution on the magnitude of the electric force, noting that the vector's magnitude changes based on proximity to the quadrants.

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Homework Statement


A thin semicircular rod is broken into two halves, the top half has a total charge +Q uniformly distributed along it, and the bottom half has a total charge -Q uniformly distributed along it.
http://imgur.com/tObt2V0

Homework Equations


Indicate the direction of the net electric force on a positive test charge placed in turn at points A, B, C.


The Attempt at a Solution


Had A's force vector pointing down and to the right, same with b and C pointing down and to the left but I am not sure about my answers.
 
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Think about the forces in the horizontal and vertical directions separately. E.g. for A, compare the horizontal forces (i.e. along the line AB) exerted by the two quadrants.
 
I can't really visualize it but my guess is that the horizontal component of +Q would be to the left and the -Q would have a horizontal component equal and opposite so to the right. The vertical component of +Q on the charges would be down, same with the -Q charge.
 
Exactly so. So the resultant force is in which direction?
 
Down and to the right. Would it be the same for both A and B. And C would be down and to the right?
 
or is the resultant straight down?
 
If the horizontal components are opposite (and equal in magnitude, since all distances are the same for the + and for the - quadrant), don't they cancel each other?
 
fgb said:
If the horizontal components are opposite (and equal in magnitude, since all distances are the same for the + and for the - quadrant), don't they cancel each other?
yeah that's what I am thinking
 
Yeah, so the resultant is straight down, like you said :)
 
  • #10
So all of the points; A,B, and C would have the same vector pointing down?
 
  • #11
The magnitude of said vector would change according to distance from the point to the quadrants (i.e., the vector is smaller for point A than for point B), but it is indeed straight down for three points :)
 
  • #12
Thank you very much.
 

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