Chemistry - Lewis Structure question

AI Thread Summary
The discussion centers on drawing Lewis structures and the placement of atoms, specifically for the molecule H2CO. Participants agree that multiple Lewis structures can be drawn, but some emphasize that the arrangement of atoms affects molecular shape and bond angles. While all proposed structures are deemed equivalent, it is noted that the best representations show hydrogen atoms spaced apart to minimize repulsion. However, there is a debate about the actual bond angles, with references to VSEPR theory suggesting that the angles are closer to 120 degrees. Ultimately, the conversation highlights the complexity of Lewis structures and their limitations in depicting molecular geometry accurately.
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I understand the idea of the Lewis Structure and the octet rule. What I don't know is where to place the atoms. And unfortunately my book doesn't explain it. They just draw the lewis structur and expect us to understand how they did it.

For example: Draw the lewis structure of H_2CO

[PLAIN]http://img46.imageshack.us/img46/7392/lewisstructure.png

The book's answer is in black. Two other scenarios I drew in red and blue. Are my other scenarios incorrect? Does where you place the outer atoms really matter?

Can someone please help?
Thanks!
 
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I would say all three are equivalent.

Edit: there is a slight problem with the molecule shape and bond angles, but if someone wants to be nitpicky about it, all three are wrong (including the one from the book). IMHO it is better to draw both hydrogen bonds on one line, to show that they are equivalent. In reality all three bond angles are close to 120 deg.
 
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all the three are equivalent indeed!
 
All three are equivalent. Lewis structures are simple drawings, they don't take into account VSEPR theory.
 
They are all correct, but the left drawing and the center drawings are the best out of all three. They show that the hydrogen's are spread as far apart from each other as possible because both of those atoms are positively charged, so they repel each other.
 
Sniperman724 said:
hydrogen's are spread as far apart from each other as possible because both of those atoms are positively charged, so they repel each other.

No, they are not spread apart as far as possible, they are very close to the sp2 angle of 120°.

Note that your logic is incomplete. If they are positively charged, oxygen must be charged negatively - and its charge must be twice higher, as the molecule is neutral. That in turn means repulsion from oxygen is stronger than repulsion between hydrogens and in effect they are not spread apart, but a little bit closer than expected.

Not sure what the real angle is, but quick googling shows this page:

http://www.800mainstreet.com/formaldehyde/Formaldehyde-Bond-length.html
 
I don't get how to argue it. i can prove: evolution is the ability to adapt, whether it's progression or regression from some point of view, so if evolution is not constant then animal generations couldn`t stay alive for a big amount of time because when climate is changing this generations die. but they dont. so evolution is constant. but its not an argument, right? how to fing arguments when i only prove it.. analytically, i guess it called that (this is indirectly related to biology, im...
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