Engineering Circuits 1 help with integration

[sammyqw]

Homework Statement

http://imgur.com/a/qlQ5z

Homework Equations

i=i(o)+1/L integration(v0) dt formula is in the attemp at a solution.

The Attempt at a Solution

http://imgur.com/a/HVjl1
For the interval 2<t<infinite . I understand that voltage at 2ms is 0 , but where did they get 2x10^-3? is that the 2ms to seconds? and how did they 50ma after the integration? I only get 10ma not 50. Thanks in advance.

 

[sammyqw]

Nevermind I think I got it. After getting 25t we do i(0.002seconds)=25(0.002)= 0.05a then for the interval 2<t<infinity i= i (0) +1/L... substituting i(o) is 0.05a so i=0.05 + integration of 0 which is 0= so the final answer is 0.05a

 

[CWatters]

Looks correct to me. I checked it this way..

V = Ldi/dt
so
di/dt = V/L
= 5*10^-3/200*10^-6
=25 amps per second (or 25t if you prefer)

Calculate I after 2mS..
25*2*10^-3 = 0.05A