Classroom Demo of Coherent Light Beam on Slits: Find Fringe Distance

AI Thread Summary
In a classroom demonstration involving coherent light of 550 nm wavelength, students calculated the frequency of light as approximately 5.45 x 10^14 Hz. They explored the distance between adjacent dark fringes using the formula ydark = [λL/d][m + 0.5], discussing the need to find the difference in positions of successive dark fringes. When immersed in a fluid with a refractive index of 1.4, the frequency of light remains the same, but the wavelength decreases, affecting fringe spacing. The group concluded that the distance between dark fringes would decrease due to the reduced wavelength in the denser medium. Understanding the relationship between wavelength, frequency, and fringe spacing was key to solving the problem.
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Homework Statement


In a classroom demonstration, a beam of coherent light of wavelength 550 nm is incident perpendicularly onto a pair of slits. Each slit has a width w of 1.2 x 10^-6 m, and the distance d between the centers of the slits is 1.8x10^-5 m. The class observes light and dark fringes on a screen that is a distance L of 2.2 m from the slits. Your notebook shows the following setup for the demonstration.

See page 11: http://apcentral.collegeboard.com/apc/public/repository/ap09_frq_physics_b.pdf

(a) Calculate the frequency of the light.

(b) Calculate the distance between two adjacent dark fringes on the screen.

The entire apparatus is now immersed in a transparent fluid having index of refraction 1.4.
(c) What is the frequency of the light in the transparent fluid?

(d) Does the distance between the dark fringes increase, decrease, or remain the same?

_____ Increase _____ Decrease _____ Remain the same

Explain your reasoning.

Homework Equations


f = c/\lambda

ydark = [\lambdaL/d][m+.5]

The Attempt at a Solution



A) f = c/\lambda
f = (3.0*10^8 m/s)/(5.5*10^(-7) m) = 165Hz

B) ydark = [\lambdaL/d][m+.5]
Hmm... would you have to find a \Deltay, though? How would you do this?
 
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Find ym and ym+1 for dark fringes and find the difference.
What is the relation between the refractive index of the material and wavelength of light traveling through?
 
science.girl said:

Homework Equations


f = c/\lambda

ydark = [\lambdaL/d][m+.5]

The Attempt at a Solution



A) f = c/\lambda
f = (3.0*10^8 m/s)/(5.5*10^(-7) m) = 165Hz
Careful with handling exponents: 8 - (-7) = ? You can tell that this number is way off.

B) ydark = [\lambdaL/d][m+.5]
Hmm... would you have to find a \Deltay, though? How would you do this?
How would you find the y position of successive dark lines? (Hint: what is m?) How would you find the difference in the y position of these dark lines?

AM
 
Andrew Mason said:
Careful with handling exponents: 8 - (-7) = ? You can tell that this number is way off.

How would you find the y position of successive dark lines? (Hint: what is m?) How would you find the difference in the y position of these dark lines?

AM

Oops! (A) should be 5.45*10^14 Hz.

For (B):
rl.bhat says to "Find ym and ym+1 for dark fringes and find the difference."
Hmm... I'm going to think about this one some more. Any hints, maybe?
I'll keep you updated.
 
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science.girl said:
For (B):
rl.bhat says to "Find ym and ym+1 for dark fringes and find the difference."
Hmm... I'm going to think about this one some more. Any hints, maybe?

Use the equation you wrote earlier:
science.girl said:
ydark = [λL/d][m+.5]

Evaluate the RHS for m and also for m+1. Subtract the two expressions and see what you get.
 
Redbelly98 said:
Use the equation you wrote earlier:


Evaluate the RHS for m and also for m+1. Subtract the two expressions and see what you get.

Oh! I understand now! Thank you very much.

For (c), I used the v = c/n, and used the velocity in the equation v = f\lambda to determine the frequency. Is this correct?

For (d), under what conditions would the dark fringes move closer or farther away? What should I be analyzing?
 
(c) Correct

(d) Two things to think about here:

1. What happens to the wavelength when the medium is changed from n=1 to n=1.4?
2. How does the fringe spacing change when wavelength is either increased or decreased?
 
Perfect! Thank you.
 

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