Coefficient of static friction experiment

AI Thread Summary
The discussion focuses on an experiment measuring the coefficient of static friction using a ramp and a tissue box with varying masses. It is established that the angle at which the box begins to move is independent of mass, as demonstrated through the physics equations governing static friction. The relationship derived shows that the static friction coefficient (μs) can be expressed as μs = tan(θ), confirming its independence from mass. However, a reminder is made regarding Galileo's experiments, which illustrate that gravitational effects also do not depend on mass, but this is not directly applicable to the static friction scenario being analyzed. The conversation effectively aligns theoretical principles with experimental observations.
physicshelpppp
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1. Problem

I am currently doing a home experiment about the coefficient of static friction. I've set up a ramp and am testing at which angle a tissue box begins to movie (with five different masses in it)... Although for every mass I use the angle seems to remain the same. The angle at which an object will start moving is independent of mass right? Mass is important when there is no friction?
 
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The angle at which an object will start moving is independent of mass right?

Have you covered the maths at school yet? If you have then try proving it that way.
 
The acceleration is given by a factor of $$ g*(sin(Θ) - μcos(Θ) )$$
yes..it doesn't thepend from mass
 
I have been looking at questions, when I do a worked question...

and the force down (weight force) on the object would be mgsinpheta and the force perpendicular is mgcospheta
which has same magnitude as normal force

so frictional force is = μsN (where is normal force is equal to perpendicular force)

therefore Ffr = μsmgcospheta
the object will start to move when the force down the slope is equal to the maximum friction force

therefore

mgsinpheta = μsmgcospheta

(therefore we can cancel the mg out on both sides)

and then we are left with μs = sinpheta/cospheta therefore μs = tanphetatherefore it is independent of mass?
 
Correct. Nice to see theory and experiment agree.
 
physicshelpppp said:
I have been looking at questions, when I do a worked question...

and the force down (weight force) on the object would be mgsinpheta and the force perpendicular is mgcospheta
which has same magnitude as normal force

so frictional force is = μsN (where is normal force is equal to perpendicular force)

therefore Ffr = μsmgcospheta
the object will start to move when the force down the slope is equal to the maximum friction force

therefore

mgsinpheta = μsmgcospheta

(therefore we can cancel the mg out on both sides)

and then we are left with μs = sinpheta/cospheta therefore μs = tanpheta


therefore it is independent of mass?
it isn't...remember the galileo experiment with gravity :)
 
Domenico94 said:
it isn't...remember the galileo experiment with gravity :)
The galileo experiment shows that the rate of fall of an object is likewise independent of mass. But that is not what is involved in the present static friction problem under investigation.

Chet
 
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