Coefficient of volumetric expansion of gasoline at different temperatures

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Homework Help Overview

The discussion revolves around the coefficient of volumetric expansion of gasoline at varying temperatures, focusing on the relationship between initial and final volumes and the implications of mass conservation in this context.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore different methods to relate volume changes to temperature variations, questioning the origin of specific equations and the assumptions regarding mass conservation. There is a focus on understanding how the expansion of gasoline affects its volume and the potential for spillage.

Discussion Status

The discussion includes various interpretations of the problem, with some participants providing equations and suggesting approaches while others express confusion about the assumptions made. There is no explicit consensus, but several participants are actively engaging with the concepts presented.

Contextual Notes

Participants note that the problem does not explicitly state the conditions under which the gasoline expands, leading to different interpretations regarding mass and volume relationships. The mention of a tank and spillage introduces additional considerations that are not clearly defined in the problem statement.

Doshke
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Homework Statement
Task: The weight of gasoline at 0 ° C is 88N. At 60 °C the weight of the same volume of gasoline is 83N. What is the coefficient of volume expansion of gasoline?
Relevant Equations
in the picture below are
I tried to solve the task in different ways, I had different ideas but none of them led me to the correct solution.

I would be grateful if someone would explain at least the initial part of the task to me.
20210214_192546.jpg

True answer: 10-3K-1
 
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Where does the equation ##\frac{m_0}{m_1}=1.06## come from? There is no change to the mass.
 
You have the right equation relating the final volume to the initial volume, ##V_f=V_i(1+\beta \Delta T).## I think the easiest way to proceed from here is to find ##V_f## assuming constant mass. Then ##\rho_i V_i=\rho_f V_f.## Perhaps you can continue from here on your own.
 
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haruspex said:
Where does the equation ##\frac{m_0}{m_1}=1.06## come from? There is no change to the mass.
The problem doesn't say anything to this effect, but it is instinctive to think that the gasoline is contained in a tank and some of the fluid spilling over when the temperature rises. (That was my impulsive original thought.) I have seen a similar problem in which both gasoline and tank expand and one has to find the amount of spilled gasoline.
 
kuruman said:
The problem doesn't say anything to this effect, but it is instinctive to think that the gasoline is contained in a tank and some of the fluid spilling over when the temperature rises. (That was my impulsive original thought.) I have seen a similar problem in which both gasoline and tank expand and one has to find the amount of spilled gasoline.
Yes, I should have been clearer.
@Doshke's algebra started by taking mass constant and computing the change in volume. That would have worked, but it then switched to taking it as a change in mass. That also would work, but unfortunately the two approaches got interwoven and cancelled, leading to the loss of the 1.06 factor.
 
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kuruman said:
You have the right equation relating the final volume to the initial volume, ##V_f=V_i(1+\beta \Delta T).## I think the easiest way to proceed from here is to find ##V_f## assuming constant mass. Then ##\rho_i V_i=\rho_f V_f.## Perhaps you can continue from here on your own.

Thank you for your help @haruspex @kuruman I managed to do the task.
This observation saved me
##\rho_i V_i=\rho_f V_f.##
 
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