Common Emitter with emitter resistance small signal model

AI Thread Summary
The discussion revolves around calculating the voltage gain (Av) and input resistance (Rin) of a common emitter amplifier using the pi model. The user successfully derived the voltage gain but struggles with the input resistance, seeking clarification on the correct formula. It is confirmed that Vbe is across the base-emitter junction and does not include external resistors. Suggestions are made to adjust the Rin formula for proper dimensional consistency, emphasizing that Rin should consider the base resistance and the emitter resistance scaled by beta. The conversation highlights the importance of accurate notation and understanding circuit relationships in small signal analysis.
Electrical_kid
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This link has the picture, for some reason it wasnt showing in this post. http://i.imgur.com/TYlb32t.jpg
Here is my problem, I am supposed to use this circuit and solve for Av and Rin. My problem is that I have solved for Av but I can't solve for Rin no matter what I use. Its very frustrating. I need to use the pi model.

Here is my work for the Av gain.

i2yiMT6.jpg


Please let me now if this is correct and then a tip on how I can solve for Rin which should be Rin = RB|| r_pi (R_E(1+B)). Is Vbe only across r_pi or r_pi and R_E?

Av = -B(R_C||R_L)/(r_pi) which is what I have in my work in the upper right middle
 
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Welcome to PF.
Is this either coursework or homework ?

small_circuit.png
 
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Baluncore said:
Welcome to PF.
Is this either coursework or homework ?
Its homework, do you think there is a typo in the Rin given? Or is the emitter resistance in the wrong place?
 
I shrank and posted the circuit.
Rin is shown as an indeterminate arrow, Is it measured at Vs of at the base terminal ?
Rin is frequency dependent because of the series C in the base circuit.
Re will appear higher resistance to Rin because it is seen through the base current gain, beta.
 
Electrical_kid said:
Please let me know if this is correct and then a tip on how I can solve for Rin which should be Rin = RB|| r_pi (R_E(1+B)). Is Vbe only across r_pi or r_pi and R_E?
Vbe is always the voltage across the active b-e junction; it doesn't embrace voltage across externally placed resistors.

Your formula for Rin looks awkward. The expressions on each side of the "||" symbol should have units of Ohms.
 
Should Rin be Rin = RB || (rpi + RE*(beta+1)) ?
 
Electrical_kid said:
Should Rin be Rin = RB || (rpi + RE*(beta+1)) ?
That looks better.
 
NascentOxygen said:
Your formula for Rin looks awkward. The expressions on each side of the "||" symbol should have units of Ohms.
If R_pi has dimension ohms then your Rin = RB || r_pi (R_E(1+B)) has dimensions of ohm || ohm2
Where has your R_pi come from ?

See schematic in post #2
Do you think Rbase = R1 || R2 ?

How is beta defined ?
Maybe; Rin = Rbase || (Re * beta)
or; Rin = Rbase || (Re * (1+beta) )
 
Baluncore, I think the reason I was having trouble is because the answer they provided was missing the plus sign, a previous professor of mine provided me a pdf file explaining how they get Rin and it definitely shows that it should be Rin = RB || ( rpi + RE(beta +1)).
 
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