Calculate Compressive Stress: 110N on 1.15cm Radius Cane

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To calculate the maximum compressive stress in the cane, the correct formula is stress equals force divided by area (F/A). The user initially misapplied the formula by confusing pressure with stress. The correct area calculation involves using the radius of the cane, specifically applying the formula for the area of a circle (A = πr^2). After clarifying the definitions, the user acknowledges the mistake and seeks further assistance. Understanding the distinction between stress and pressure is crucial for accurate calculations.
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----A man leans down on a cane with a vertical force of 110.00N. The narrowest part of the cane has a radius of 1.15cm. What is the maximum compressive stress in the cane?----

For this problem I thought I needed to calculate stress, which is P/A . Pressure is the Force/Area...so I did 110N / Pi 0.0115^2 . And then I divided that answer to get the stress, but it was wrong. Can anyone help me figure out what I did wrong? Thanks :)
 
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Stress is not P/A, it is F/A.

(Note : Stress is a tensor, whose elements are determined from the components of force and area vectors, while pressure is a scalar.)
 
oh my bad...thanks :)
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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