Confusion in using the continuity equation here

AI Thread Summary
Assuming "Properties in the tank are uniform, but time-dependent" leads to the validity of (DmDt)sys=0 because the mass of the system remains invariant over time, despite changes in the control volume. The system encompasses all matter inside, entering, or exiting the control volume, while the mass within the control volume changes as time progresses. The first integral represents the instantaneous mass in the control volume, and the second integral accounts for mass flow out of the container. This distinction clarifies that the perceived change in mass does not contradict the continuity equation. Understanding these concepts is crucial for correctly applying the continuity equation in fluid dynamics.
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Homework Statement
I feel that the mass within the system changes over time, but this perception contradicts the solution.
Relevant Equations
continuity equation
Q: Why does assuming "Properties in the tank are uniform, but time-dependent" lead to the validity of
(DmDt)sys=0? Doesn't the mass within the system change over time?
reference.
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tracker890 Source h said:
Homework Statement: I feel that the mass within the system changes over time, but this perception contradicts the solution.
Relevant Equations: continuity equation

Q: Why does assuming "Properties in the tank are uniform, but time-dependent" lead to the validity of
(DmDt)sys=0? Doesn't the mass within the system change over time?
reference.
View attachment 335945
The mass of the system is the total mass, i.e. what’s inside and what’s outside the control volume at a particular time. It is invariant (at least in classical physics?). at ##t=0## all of the system is inside the control volume, as time progresses some portion of the system is outside. That ∫ on the left (unsteady) represents what portion of the system is inside (only) the control volume at a particular time.

Summarizing: The system is not the control volume. The system is the stuff (matter) inside the control volume, on its way into the control volume, or what has left the control volume.
 
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To add a little to @erobz, the first integral ##\int_{\small CV}\rho dV## is the instantaneous mass within the control volume. This mass changes with time. So, ##\frac{\partial}{\partial t}\int_{\small CV}\rho dV## represents the rate of change of mass within the tank. The second integral represents the rate at which mass is flowing out through the neck of the container.
 
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