Calculating the Force on a 65kg Barrel Rolling Down a 1.2m Ramp

AI Thread Summary
To calculate the constant force on a 65 kg barrel rolling down a 1.2 m ramp, one can use the formula F = ma, where 'm' is mass and 'a' is acceleration. The barrel reaches a velocity of 4.2 m/s upon leaving the ramp, indicating that kinetic energy is gained during the descent. The discussion highlights that additional information, such as the angle of the ramp, could clarify the problem. It is suggested that the force of gravity plays a significant role in this scenario. Ultimately, the force exerted on the barrel can be expressed in Newtons based on the weight and acceleration.
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A barrel of oil with a mass of 65 kg is rolled down a 1.2 m ramp. Due to a constant force exerted on it, the barrel reaches a velocity of 4.2 m/s just on leaving the ramp. Find the constant force on the barrel while it is on the ramp and express your answer in the form of a sentence relating force, change in velocity, distance, and direction.

what would the formula be for this question? :\

Mass: 65kg
Velocity: 4.2m/s
acceleration: 1.2m x 9.81m/s = 11.77m/s
 
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This question isn't answerable without additional information. Are you sure you copied the question correctly?
 
Hello,
I did copy it right, I copied and pasted the question from the assignment I was given, what kind of information is missing?
 
I agree the problem is a little vague. It's plausible that the force is just the force of gravity.
 
Right. In that case, this question becomes simple.

How much kinetic energy did the object gain in going down the ramp? Considering that W=Fd and you know d, what's F?
 
it didnt give you an angle?

then you could calculate both the force of gravity and the force of the object rolling down the incline?
You can use this formula (very basic)

Fy=mg

your answer should be in Newtons.

im not sure though but maybe that velocity is just information to mislead you?

Edit: never mind. but the force exerted on the y-direction can still be found with that
 
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