Correct method of measuring a pulse

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SUMMARY

The discussion focuses on measuring the power output of a single pulse through an air core transformer using an oscilloscope. Key measurements include instantaneous voltage and current, with the formula P(t) = V(t) * I(t) being essential for calculating power. A high-bandwidth current probe is recommended for accurate measurements, and an alternative method involves using a low-resistance shunt resistor to gauge current. The pulse duration is approximately 26 microseconds, and the goal is to analyze the effects of different wire gauges and turns on the secondary output.

PREREQUISITES
  • Understanding of oscilloscope operation and measurement techniques
  • Knowledge of electrical power calculations using P(t) = V(t) * I(t)
  • Familiarity with current probes and their bandwidth specifications
  • Basic principles of transformer operation and pulse characteristics
NEXT STEPS
  • Research high-bandwidth current probes suitable for pulse measurements
  • Learn about low-resistance shunt resistor applications in current measurement
  • Explore oscilloscope math functions for power calculations
  • Investigate the impact of wire gauge and turns on transformer performance
USEFUL FOR

Electrical engineers, hobbyists working with transformers, and anyone involved in pulse measurement and power analysis will benefit from this discussion.

James G Deye
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I am currently working a project to evaluate the power output of a single pulse through an air core transformer. Using a scope to measure the secondary output and I am confused on what voltage to use. Scope shows DC voltage, peak voltage, drop Voltage differential of peak and drop voltage. Would a current probe also be advantages for these measurements. The single pulse we capture is about 26 microseconds from peak to end. We hope to calculate though these measurements the forcast of different wire guages and number of turns on the secondary.


Jamie
 
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James G Deye said:
I am currently working a project to evaluate the power output of a single pulse through an air core transformer. Using a scope to measure the secondary output and I am confused on what voltage to use. Scope shows DC voltage, peak voltage, drop Voltage differential of peak and drop voltage. Would a current probe also be advantages for these measurements. The single pulse we capture is about 26 microseconds from peak to end. We hope to calculate though these measurements the forcast of different wire guages and number of turns on the secondary.

Welcome to the PF, Jamie. To get a clear picture of the power in the pulse, you will need to measure the instantaneous voltage and current, and calculate the product P(t) = V(t) * I(t).

If you have a good (high-bandwidth) current probe, then you can put that on Ch2 of your 'scope, and use the math function to give you the product to display the P(t) graph.

If you're current probe is not of high enough bandwidth, you could put a low-resistance shunt at the low-side of the coil that you are driving (with one side of the resistor to ground), and measure that voltage to get a picture of what the current is. This is slightly more invasive as measurements go, but as long as you keep the voltage drop across the shunt small compared to the total coil voltage, you should get a pretty accurate measurement.
 

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