Coulombs Law and Electric Charges

AI Thread Summary
A charge of 7.00 mC is positioned at each corner of a square with sides measuring 0.80 m, and the discussion revolves around calculating the force on each charge. The problem presents challenges in determining the net force, particularly for one of the charges. Participants suggest leveraging the symmetry of the square to simplify the calculations, noting that the forces acting on each charge are equivalent in direction and magnitude. Understanding the geometry, such as the properties of an equilateral triangle, is highlighted as beneficial for solving the problem. Overall, the conversation emphasizes the importance of symmetry in electric charge interactions.
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Likewise, this similar problem also has me stumped
A charge of 7.00 mC is placed at each corner of a square 0.80 m on a side. Determine the magnitude of the force on each charge.

Any help would be greatly appreciated!
 
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OMG,this is funny... :smile: :smile: :smile: :smile: :smile:

Do you know what an equilateral triangle is?

Daniel.
 
I'm insulted.

Yes, I know what an equilateral triangle is. It has three sides of equal length, and all three angles are 60 degrees. As I stated, I found the net force on two of the points, but Q(1) is giving me issues. Obviously the way I'm trying is wrong, so I'd like help, thank you.
 
You deleted the problem.Anyway,since you know what a equilateral triangle is,u might use the fact that the problem is symmetric (actually the geometry) so the directions of the forces are equivalent.If the charges were all 3 equal,then the problem would b solved if u managed to find the net foce acting only on one angle,since on the other two is practically the same,in modulus,of course.

Daniel.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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