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swede5670
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Homework Statement
What are the magnitude and direction of the electric field at a point midway between a -9.0 µC and a +6.0 µC charge 3.0 cm apart? Assume no other charges are nearby.
Homework Equations
Fe= {K(q1)(q2)}/d^2
k = (8.99 x 10^9)
The Attempt at a Solution
First I converted the µC to C =
-9 µC = -.000009 C
6 µC = .000006
Then convert 3 cm to mm = .03
(8.99 x 10^9) (-.000009) ( .000006 ) = -.48546
-.48546/d^2
-.48546/ .03
-539.4
My final answer is -539.4 but I know its wrong, can anyone tell me what I did incorrectly?