Crane Efficiency: 5.10 x 10^5 Energy to Lift 1000kg 32m

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To calculate the efficiency of a crane lifting 1000 kg to a height of 32 m using 5.10 x 10^5 joules of energy, one must first determine the energy required for the lift, which is calculated using the formula E = mgh (mass x gravity x height). The efficiency can then be expressed as the ratio of the energy required to the energy used, where the energy used is 5.10 x 10^5 joules. It is important to note that while the discussion mentions power, the focus should remain on energy for this calculation. The correct formula for efficiency in this context is Efficiency = (Energy required / Energy used) x 100%. Understanding these concepts is crucial for accurately assessing crane efficiency.
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What is efficiency of a crane that uses 5.10 x 10 to the fifth power of energy to lift 1000kg a vertical height of 32.0 m ?

geez what formula do i use lol i tried using the heat energy formula but to no avail T_T someone offer help lol like what formula do i use?
 
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How much energy is required to lift the mass to the required height?
Efficiency = power needed / power actually used
 
5.10 x 10 to the fifth power of energy would this be the power actually used?
 
Yes. Well, energy, not power, but you can use the energy to calculate the efficiency in this case. Technically, power is energy per unit time.
 
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