Current in a rectangle on a hinge

AI Thread Summary
The discussion focuses on calculating the torque acting on a rectangular coil of wire hinged along one side and positioned at an angle to a magnetic field. The coil has 15 turns, dimensions of 10 cm by 5 cm, and carries a current of 0.90 A in a magnetic field of 0.50 T. The torque formula τ = μ × B and the magnetic moment μ = NiA are used, leading to an initial calculation of τ = 0.16875 Nm. Participants suggest reviewing the angle used in the calculations, particularly the implications of the 30° angle on the direction of the magnetic moment. Understanding the correct application of the sine function in relation to the angle is crucial for accurate torque determination.
lodovico
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Homework Statement


Figure 29-36 shows a rectangular, 15-turn coil of wire, 10 cm by 5.0 cm. It carries a current of 0.90 A and is hinged along one long side. It is mounted in the xy plane, at an angle of 30° to the direction of a uniform magnetic field of 0.50 T. Find the magnitude and direction of the torque acting on the coil about the hinge line.

Homework Equations



\tau=μ × B
μ=NiA

The Attempt at a Solution



I don't know how to approach this. I tried to plug in numbers into ^ formula
 
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If you'll show more details of how you tried the calculation, we will be able to see where you're having trouble.
 
τ=μ × B
μ=NiA

τ=NiABsin30
τ=(15)(.9)(.1*.05)(.5)sin30

τ=.16875 Nm
 
lodovico said:
τ=μ × B
μ=NiA

τ=NiABsin30
τ=(15)(.9)(.1*.05)(.5)sin30

τ=.16875 Nm

See if you can figure out why the 30o is not correct here. You'll need to think about the direction of \vec{\mu}
 
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