Definition of 'with the vertical' in this question?

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SUMMARY

The discussion clarifies the term "with the vertical" in the context of centripetal force and acceleration for a car moving in a circular path. It establishes that the angle with the vertical is determined by the ratio of the vertical force supporting the car against gravity and the horizontal centripetal force. Specifically, a strictly vertical force is at 0 degrees, while a strictly horizontal force is at 90 degrees. The angle can be calculated using the arc tangent of these force components.

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ehf
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Homework Statement


J5VjCPu.jpg

(please ignore something that is not english)

Homework Equations


ac=v^2/r
Fc is about 6.0E3 N and ac is about 5.0 m/s^2
(b) is the problem...

The Attempt at a Solution


what is 'with the vertical' here? the direction/opposite of ac or the direction of v?
 
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It means the angle with the vertical. So a strictly vertical force downward would be 0 degrees. A strictly horizontal (sliding) force would be 90 degrees.
 
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sliding=horizontal=velocity direction and vertical=ac direction then?
 
ehf said:
sliding=horizontal=velocity direction and vertical=ac direction then?
The force applied to the car by the pavement will consist of 2 components:
- 1) There will be a vertical component that supports the mass of the car against gravity.
- 2) There will be a horizontal centripetal force that holds the car along its circular path.

The angle of the total force against the car with vertical will be an arc tangent of the ratio of these forces.
 
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.Scott said:
The force applied to the car by the pavement will consist of 2 components:
- 1) There will be a vertical component that supports the mass of the car against gravity.
- 2) There will be a horizontal centripetal force that holds the car along its circular path.

The angle of the total force against the car with vertical will be an arc tangent of the ratio of these forces.

Oh thank you now I understand the meaning
 

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