Derivation of heat transfer equation for spherical coordinates

AI Thread Summary
The discussion focuses on deriving the heat transfer equation in spherical coordinates, starting from the fundamental heat transfer equation dQ/dt = λAΔT/Δr. The user expresses confusion about how to proceed, particularly regarding the limit of ΔT/Δr as Δr approaches zero and the volume element in spherical coordinates. A critical point raised is that the heat flow rate, Qdot, can vary along Δr, leading to the need for a derivative d(Qdot)/dr. The conversation highlights the importance of maintaining consistent dimensions in equations and emphasizes the challenge of substituting Qdot with an expression involving the dissipation rate per volume. The final goal is to arrive at the equation -d/dr{λr(dT/dr)} = r²q_dot.
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Homework Statement



attachment.php?attachmentid=47491&stc=1&d=1337619652.png


where λ= thermal conductivity
\dot{q}= dissipation rate per volume

Homework Equations



qx=-kA\frac{dT}{dx}

The Attempt at a Solution



I don't know where to start from to be honest, so any help would be greatly appreciated
 

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I've had to think on this one for some time; I hope what I write is correct:

Start with the fundamental equation for heat transfer:

dQ/dt = λAΔT/Δr
where
dQ/dt = Qdot = rate of heat flow across area A;
λ = conductivity;
ΔT = temperature difference across volume element AΔr.

What is ΔT/Δr in the limit as Δr → 0?

Then: what is the volume element AΔr in spherical coordinates? (Heat flows thru the volume element from one side of area A to the other side, also of area A, the two sides separated by Δr. )

Now for the big step: realize that Qdot need not be constant along Δr. In other words, Qdot can be different for the two end-sides of your elemental volume. So in the limit the derivative d(Qdot)/dr can be finite. So your last equation is to equate how Qdot changes along Δr to what the problem calls the "dissipation rate per volume".
 
OK so this is what I got:

-λ4r2\frac{dT}{dr} + \dot{q}4∏r2dr = ρc4∏r2\frac{dT}{dτ}dr -4∏r2(λ\frac{dT}{dr} + \frac{d}{dr}(λ\frac{dT}{dr})dr)

Is this correct?

Since the flow is steady the time derivative \frac{dT}{dτ}=0

But then when I rearrange everything I get:

r2\frac{d}{dr}(λ\frac{dT}{dr}) + \dot{q}r2 = 0

can I just take the r2 inside the differential bracket?

EDIT: missed out a dr in the rearranged equation:

r2\frac{d}{dr}(λ\frac{dT}{dr})dr + \dot{q}r2 = 0
 
Last edited:
Your (edited) equation has incompatible terms: the first is infinitesimal, the second isn't. Plus, the terms' dimensions don't agree: the first one's are (using SI) J/sec whereas the second one's are J/(sec-m).

Ironically, your unedited equation has matching dimensions but you can't smuggle the r2 into the d/dr bracket as you wondered. (That's just basic calculus: for example, r2d/dr(r2) = 2r3 whereas d/dr(r4) = 4r3.)

Going back to my "first principles" equation , Q_dot = λAΔT/Δr, you seem to have correctly determined that, in spherical coordinates, A = 4πr2 and, of course, ΔT/Δr → dT/dr. So your remaining task, and it does take some thinking, is to somehow get rid of Q_dot and substitute for it an expression containing q_dot. (Sorry, I haven't learned the itex thing yet). So that you wind up with
-d/dr{λr(dT/dr)} = r2q_dot. That is really the hard part about this problem.
 

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