Derivative of Hyperbolic Trigonometric Function

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gurtaj
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Homework Statement



derivative of (e^x-e^-x)/(e^x+e^-x)


Homework Equations





The Attempt at a Solution



attachment.php?attachmentid=35933&stc=1&d=1306367699.jpg

This answer was marked 2/4 on the test, can anyone help me get the right answer please ?
 

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Hi gurtaj! :smile:

I don't understand your first step: you have [itex](e^x-e^{-x})(e^x+e^{-x})^{-1}[/itex] and you wish to derive it. The product rule says that this equals

[tex](e^x-e^{-x})^\prime(e^x+e^{-x})^{-1}+(e^x-e^{-x})((e^x+e^{-x})^{-1})^\prime[/tex]

You did the second part of the sum allright, but you didn't differentiate anything in the first part of the sum...
 
Last edited:
oh sorry the next step after
[itex](e^x-e^{-x})(e^x+e^{-x})^{-1}[/itex]
I meant to put
[itex](e^x+e^{-x}) (e^x+e^{-x})^{-1} + (e^x-e^{-x})(-1)(e^x+e^{-x})^{-2}(e^x-e^{-x})[/itex]

so i did
derivative of the first one times second , then derivative of the second one times first
 
i think that is right too but somehow it was marked 2/4, and the teacher wrote expand and simplify
 
micromass said:
Yes, the final answer is correct. But if I was your teacher I would have given 2/4 too. The point is that your notation is really messy and you can't really see what you're doing :frown: And you're making the problem longer than it needs to be...

The teacher didn't cut 2 marks for messy notations or making the problem longer, she said its the answer that's wrong. She said you can expand that answer even more
 
I tried Quotient rule and end up with same answer

[itex](e^x-e^{-x})/(e^x+e^{-x})[/itex]

[itex](e^x+e^{-x}) (e^x+e^{-x})-(e^x-e^{-x})(e^x-e^{-x})/ (e^x+e^{-x})^{2}[/itex]

[itex]1-((e^x-e^{-x})^{2}/ (e^x+e^{-x})^{2})[/itex]
 
gurtaj said:
She said you can expand that answer even more

Ohhhh, I see what's going on here.

Hint: Look and sinh and cosh.

You still the problem right though. I can't see why your teacher would give you half credit.

(Also, look at tanh)
 
gb7nash said:
Ohhhh, I see what's going on here.

Hint: Look and sinh and cosh.

You still the problem right though. I can't see why your teacher would give you half credit.

(Also, look at tanh)

We never learned Hyperbolic function, so she wasn't expecting that from us