Derivative of Hyperbolic Trigonometric Function

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SUMMARY

The discussion centers on finding the derivative of the hyperbolic function defined as (e^x - e^-x) / (e^x + e^-x). Participants highlight the use of the product rule and quotient rule for differentiation, emphasizing that simplification is crucial for clarity. The original poster received a low score due to messy notation and a lack of simplification in their final answer. The conversation suggests that understanding hyperbolic functions like sinh and cosh could enhance comprehension of the topic.

PREREQUISITES
  • Understanding of calculus, specifically differentiation techniques
  • Familiarity with the product rule and quotient rule in calculus
  • Knowledge of hyperbolic functions, particularly sinh and cosh
  • Ability to simplify algebraic expressions and fractions
NEXT STEPS
  • Study the differentiation of hyperbolic functions, focusing on sinh and cosh
  • Practice applying the quotient rule in various calculus problems
  • Learn how to simplify complex fractions and expressions in calculus
  • Explore common mistakes in calculus notation and how to avoid them
USEFUL FOR

Students studying calculus, particularly those learning about derivatives of hyperbolic functions, and anyone seeking to improve their mathematical notation and simplification skills.

gurtaj
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Homework Statement



derivative of (e^x-e^-x)/(e^x+e^-x)


Homework Equations





The Attempt at a Solution



attachment.php?attachmentid=35933&stc=1&d=1306367699.jpg

This answer was marked 2/4 on the test, can anyone help me get the right answer please ?
 

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Hi gurtaj! :smile:

I don't understand your first step: you have (e^x-e^{-x})(e^x+e^{-x})^{-1} and you wish to derive it. The product rule says that this equals

(e^x-e^{-x})^\prime(e^x+e^{-x})^{-1}+(e^x-e^{-x})((e^x+e^{-x})^{-1})^\prime

You did the second part of the sum allright, but you didn't differentiate anything in the first part of the sum...
 
Last edited:
oh sorry the next step after
(e^x-e^{-x})(e^x+e^{-x})^{-1}
I meant to put
(e^x+e^{-x}) (e^x+e^{-x})^{-1} + (e^x-e^{-x})(-1)(e^x+e^{-x})^{-2}(e^x-e^{-x})

so i did
derivative of the first one times second , then derivative of the second one times first
 
OK, so that expression will evaluate easily to the answer...
 
i think that is right too but somehow it was marked 2/4, and the teacher wrote expand and simplify
 
Yes, the final answer is correct. But if I was your teacher I would have given 2/4 too. The point is that your notation is really messy and you can't really see what you're doing :frown: And you're making the problem longer than it needs to be...
 
Quotient rule will greatly simplify your answer, and be much cleaner.
 
micromass said:
Yes, the final answer is correct. But if I was your teacher I would have given 2/4 too. The point is that your notation is really messy and you can't really see what you're doing :frown: And you're making the problem longer than it needs to be...

The teacher didn't cut 2 marks for messy notations or making the problem longer, she said its the answer that's wrong. She said you can expand that answer even more
 
I tried Quotient rule and end up with same answer

(e^x-e^{-x})/(e^x+e^{-x})

(e^x+e^{-x}) (e^x+e^{-x})-(e^x-e^{-x})(e^x-e^{-x})/ (e^x+e^{-x})^{2}

1-((e^x-e^{-x})^{2}/ (e^x+e^{-x})^{2})
 
  • #10
Then I guess your teacher wants you to simplify your answer. Put your fractions on one denominator and work out the squares...
A bit silly to subtract points for that, unless she stated that your answer must be simplified...
 
  • #11
gurtaj said:
She said you can expand that answer even more

Ohhhh, I see what's going on here.

Hint: Look and sinh and cosh.

You still the problem right though. I can't see why your teacher would give you half credit.

(Also, look at tanh)
 
  • #12
gb7nash said:
Ohhhh, I see what's going on here.

Hint: Look and sinh and cosh.

You still the problem right though. I can't see why your teacher would give you half credit.

(Also, look at tanh)

We never learned Hyperbolic function, so she wasn't expecting that from us
 
  • #13
I have no idea then. I think your instructor's crazy.
 
  • #14
gb7nash said:
I have no idea then. I think your instructor's crazy.

I second that! :smile:
 

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