- #1
Rugile
- 79
- 1
Homework Statement
We have two coordinate functions of time, as follows: x(t) = 5 + 2t ; y(t) = -3+3t+2t2. Find velocity [itex]\vec{v}[/itex], acceleration [itex]\vec{a}[/itex], tangential acceleration [itex]\vec{a_t}[/itex], normal acceleration [itex]\vec{a_n}[/itex] functions of time and their magnitude's functions of time.
Homework Equations
[itex]\frac{dx}{dt} = v[/itex]
[itex]\frac{dv}{dt} = a[/itex]
The Attempt at a Solution
So I guess [itex]v_x = \frac{dx(t)}{dt} = 2[/itex] and [itex]v_y = \frac{dy(t)}{dt} = 3+4t[/itex]. And so [itex]\vec{v_x} = 2\vec{i_y}[/itex]; [itex]\vec{v_y} = (3+4t)\vec{i_y}[/itex]. I guess that [itex]v = \sqrt{v_x^2 + v_y^2} = \sqrt{13+24t+16t^2}[/itex]. But then how do you find the vector of v? And also, am I right saying that at is derivative of vx and an is derivative of vy?