Calculating Max Speed for 5G Turn in Aircraft

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To calculate the maximum speed of an aircraft fully banked at a 90-degree angle during a turn with a radius of 100 meters and a maximum G-force of 5G, the formula G = V^2/r is used. The correct calculation involves converting the G-force into acceleration, where 5G equals approximately 49 m/s². Using the formula, the maximum speed V is calculated as V = √(5 * 100), resulting in a maximum speed of 70 m/s. However, there is a note that the initial calculation of 70 m/s is incorrect due to a misunderstanding of units. The discussion emphasizes the importance of proper unit conversion in such calculations.
chinook177
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Ok need a bit of help checking I've got this right please.

If an aircraft (Unknown weight) banks into a turn of radius 100m at a bank angle of 90deg ie fully banked into the turn and the max G the plane/pilot can pull is 5G what is the maximum speed the aircraft can travel?

I've worked it out using G = V^2/r

V = √(5*100)
V = 70 mps

Cheers
 
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chinook177 said:
... at a bank angle of 90deg ie fully banked ...

IMHO if the lift force of the plane is at right angles to the plane of the wings and the plane is fully banked. what force will support the weight of the plane?
 
chinook177 said:
Ok need a bit of help checking I've got this right please.

If an aircraft (Unknown weight) banks into a turn of radius 100m at a bank angle of 90deg ie fully banked into the turn and the max G the plane/pilot can pull is 5G what is the maximum speed the aircraft can travel?

I've worked it out using G = V^2/r

V = √(5*100)
V = 70 mps
You have to convert 5G to an acceleration with units in m/sec^2. I assume you have done this because √(5*100)≠70 and 70 is the right answer.

AM
 
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