What is the diameter of the bicycle tire?

AI Thread Summary
To determine the diameter of a bicycle tire, the relationship between angular speed and linear speed is used, with the equations v = rw and w = v/r. Given an angular speed of 30 radians/s and a linear speed of 10 m/s, the radius can be calculated by rearranging the equations. The correct calculation yields a radius of 0.33 meters, resulting in a diameter of 0.66 meters or 66 cm. The discussion emphasizes the importance of correctly manipulating equations to avoid confusion in solving for the desired variable. The final conclusion confirms the calculated diameter based on the provided speeds.
keithcuda
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Homework Statement


A bicycle tire rotates at 30 radians/s. If the bicyclist travels at 10 m/s, what is the diameter of the tire?

Homework Equations


I found; for angular speed, w=v/r
and for linear speed; v=rw
where v=m/s
and w=radians/s

So if i am thinking correctly, i already know my angular speed of 30 radians/s
and my linear speed is 10m/s
so now i just need to find the radius or diameter of the tire.

If i try solving for r, i get completely different answers.

The Attempt at a Solution


bike tire.jpg
 
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How did you get the 300 in your first solution? Remember what you're solving for, and that you have to treat both sides of an equation the same way.
 
Bystander said:
How did you get the 300 in your first solution? Remember what you're solving for, and that you have to treat both sides of an equation the same way.
good question... It's been a long day here at the power plant.

I always tend to get confused when i try to solve for certain things. i was wanting to solve for "r" by multiplying both sides by 10.

so now i am getting; 30rad/s = 10m/s / r
r=10/30
r=.33

so that is just a radius. The diameter would be .66 meters? or 66cm...?
 
You got that for the second solution, and now for the first solution. That's what I get. And, that should be the diameter.
 
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Bystander said:
You got that for the second solution, and now for the first solution. That's what I get. And, that should be the diameter.
It makes much more sense when I solve for "r" the proper way... :wThanks for the help
Cheers
Keith
 
Have a happy.
 
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