Diffraction condition - Kittel's Intro to Solid State Physics 8th ed.

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SUMMARY

The discussion focuses on deriving equation (22) from Kittel's "Introduction to Solid State Physics" (8th edition), specifically the diffraction condition represented as 2\vec{k}\cdot\vec{G} + G^2 = 0. The derivation begins with the condition Δ\vec{k} = \vec{G}, leading to the relationship between the incident wave vector \vec{k}, the outgoing wave vector \vec{k'}, and the reciprocal lattice vector \vec{G}. The confusion arises from the sign discrepancy in the dot product, where the user questions why Kittel's equation lacks a negative sign before the dot product.

PREREQUISITES
  • Understanding of wave vectors, specifically incident (\vec{k}) and outgoing (\vec{k'}) wave vectors.
  • Familiarity with the concept of reciprocal lattice vectors (\vec{G}).
  • Knowledge of the law of cosines in vector mathematics.
  • Basic grasp of diffraction conditions in solid-state physics.
NEXT STEPS
  • Review the derivation of the diffraction condition in solid-state physics texts.
  • Study the law of cosines and its application in vector analysis.
  • Explore the significance of reciprocal lattice vectors in crystallography.
  • Investigate common errors in vector mathematics related to dot products.
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Students and educators in solid-state physics, particularly those studying diffraction phenomena and vector analysis in crystallography.

DiogenesTorch
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Homework Statement



How to derive equation (22) on page 31 of Kittel's Intro to Solid State Physics 8th edition.

The equation is: 2\vec{k}\cdot\vec{G}+G^2=0


Homework Equations



The diffraction condition is given by \Delta\vec{k}=\vec{G} which from what I can surmise is the starting point for the derivation

Here are some other relevant equations/definitions
<br /> \begin{align*}<br /> \vec{k} &amp; &amp; \text{ incident wave vector} \\<br /> \vec{k&#039;} &amp; &amp; \text{ outgoing\reflected wave vector} \\<br /> \Delta \vec{k&#039;} = \vec{k&#039;}-\vec{k} &amp; &amp; \text{ scattering vector} \\<br /> \vec{G} &amp; &amp; \text{ reciprocal lattice vector} \\<br /> \end{align*}<br />



The Attempt at a Solution



Starting with the diffraction condition \Delta\vec{k}=\vec{G}

<br /> \begin{align*}<br /> \Delta\vec{k} &amp;= \vec{G} &amp; \\<br /> \vec{k&#039;}-\vec{k} &amp;= \vec{G} &amp; \\<br /> \vec{k}+\vec{G} &amp;= \vec{k&#039;} &amp; \\<br /> |\vec{k}+\vec{G}|^2 &amp;= |\vec{k&#039;}|^2 &amp; \text{If 2 vectors are equal, their squared magnitudes are equal}\\<br /> |\vec{k}+\vec{G}|^2 &amp;= |\vec{k}|^2 &amp; \text{since magnitudes k and k&#039; are equal}\\<br /> \end{align*}<br />

Using the law of cosines we now have

<br /> \begin{align}<br /> |\vec{k}+\vec{G}|^2 &amp;= |\vec{k}|^2 &amp; \nonumber \\<br /> |\vec{k}|^2 + |\vec{G}|^2 -2|\vec{k}||\vec{G}|\cos\theta &amp;= |\vec{k}|^2 &amp; \text{(1)} \\<br /> \end{align}<br />

\cos\theta is the cosine of the angle between the vectors \vec{k} and \vec{G} which is just

<br /> \begin{align*}<br /> \cos\theta=\frac{\vec{k}\cdot\vec{G}}{|\vec{k}||\vec{G}|}<br /> \end{align*}<br />

Substituting the above into equation (1)

<br /> \begin{align*}<br /> |\vec{k}|^2 + |\vec{G}|^2 -2\vec{k}\cdot\vec{G} &amp;= |\vec{k}|^2 \\<br /> |\vec{G}|^2 -2\vec{k}\cdot\vec{G} &amp;= 0 \\<br /> G^2 -2\vec{k}\cdot\vec{G} &amp;= 0 \\<br /> \end{align*}<br />

However the book is showing 2\vec{k}\cdot\vec{G} + G^2 = 0

Why is Kittel losing the minus sign in front of the dot product? I have been scratching my head for hours and can't find my error. I know this is some bone-headed oversight on my part but can't seem to find my error.


Thanks in advance
 
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If \theta is the angle between \vec{k} and \vec{G} then the angle in the law of cosines should be 180^o-\theta
 

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