Direction of magnetic field and physics principle?

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SUMMARY

A proton traveling at a speed of 3.00 x 106 m/s north experiences a magnetic force of 1.50 x 10-14 N upward. The magnitude of the magnetic field is calculated to be 3.13 x 10-2 T, assuming the magnetic field is perpendicular to the proton's velocity. The right-hand rule is utilized to determine the direction of the magnetic field, which is essential for solving problems involving charged particles in magnetic fields. The physics principle relevant to this scenario is the concept of unbalanced forces acting on charged particles.

PREREQUISITES
  • Understanding of the Lorentz force equation: Fm = qvB
  • Familiarity with the right-hand rule for determining magnetic field direction
  • Basic knowledge of magnetic fields and their properties
  • Concept of unbalanced forces in physics
NEXT STEPS
  • Study the application of the Lorentz force in different scenarios
  • Learn more about the right-hand rule and its variations
  • Explore the relationship between velocity, magnetic field, and force in charged particles
  • Investigate the effects of magnetic fields on other charged particles, such as electrons
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of charged particles in magnetic fields, particularly in the context of electromagnetism.

A123
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Homework Statement


A proton traveling at a speed of 3.00*10^6 m/s north through a magnetic field experiences a force of 1.50*10^-14N up. What is the magnitude and direction of the magnetic field? Include the physics principle

Homework Equations


Fm=qvB[/B]

The Attempt at a Solution


I solved for a B of 3.13*10^-2T but my problem lies in applying the hand rules to find the direction of the field. Which of the directions, north or up would be referring to the piece of paper that the question is on? And would the physics principle be unbalanced forces?
 
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Hello, A123. Welcome to PF!

I guess you are meant to assume that the magnetic field is perpendicular to the velocity of the proton. Otherwise, there are an infinite number of possible answers to the question. (Why?)

With that assumption, you can answer the question. You don't need to worry about "referring to the piece of paper that the question is on". Imagine that you go outside and that you face north. Since the proton is traveling north, you can think of the proton as moving away from you parallel to the ground. The force is "up", which means that the force points vertically upward (perpendicular to the ground). You should be able to use the right hand rule to determine the direction of the field.

I'm not sure what is meant by "include the physics principle".
 
TSny said:
Hello, A123. Welcome to PF!

I guess you are meant to assume that the magnetic field is perpendicular to the velocity of the proton. Otherwise, there are an infinite number of possible answers to the question. (Why?)

With that assumption, you can answer the question. You don't need to worry about "referring to the piece of paper that the question is on". Imagine that you go outside and that you face north. Since the proton is traveling north, you can think of the proton as moving away from you parallel to the ground. The force is "up", which means that the force points vertically upward (perpendicular to the ground). You should be able to use the right hand rule to determine the direction of the field.

I'm not sure what is meant by "include the physics principle".
Thanks that makes sense. I just overthought it way to much
 

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