Do These Vector Lines Intersect or Are They Skew?

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The discussion focuses on determining whether two given vector lines intersect or are skew. The calculations show that for a specific value of 'a', the lines intersect at the coordinates (6, 13, -4). When comparing components of the lines, it is confirmed that the lines are skew when the values of λ and μ yield different results for the k components. Participants clarify that the lines being skew is established by the inconsistency in these components. The final conclusion is that the lines are indeed skew unless the specific value of 'a' is set to 5, allowing for intersection.
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1.Consider the two straight lines:
2λi+(1+4λ)j+(3-3λ)k
(4+μ)i+(3+5μ)j+(-6+μ)k

a) Show lines are skew when a=3.
b) Find value of a for which lines intersect and state coordinates of point of intersection


2.
2λi+(1+4λ)j+(3-3λ)k=(4+μ)i+(3+5μ)j+(-6+μ)k

comparing i components:
(1)
2λ=4+μ
λ=(4+μ)/2

comparing j components:
(2)
1+4λ=3+5μ
λ=(2+5μ)/4

(1)=(2)
(4+μ)/2=(2+5μ)/4
16+4μ=4+10μ
μ=2

sub into (1)
λ=(4+μ)/2
λ=(4+2)/2
λ=3

Different values so the lines are skew

d) Find a value of a for which the lines intersect and state the coordinates of the point of intersection.
r1=2λi+(4λ+1)j+(a-3λ)k

r2=(μ+4)i+(5μ+3)j+(μ-6)k

I need to find the value of a for which the lines intersect and state the coordinates of point of intersection.

λ=3
μ=2

LHS a-3λ=μ-6
a-3(3)=2-6
a-9=-4
a=5

r2=4i+3j-6k+μ[i+5j+k]
r2=4i+3j-6k+2[i+5j+k]
r2=4i+3j-6k+2i+10j+2k
6i+13j-4k

coordinates of point of intersection are:
(6, 13, -4)

could somebody tell me if I'm on the right track here please?
 
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Hi lemon
lemon said:
1.Consider the two straight lines:
2λi+(1+4λ)j+(3-3λ)k


It should be : 2λi+(1+4λ)j+(a-3λ)k

Different values so the lines are skew
What do you mean by "different values" ? You only find one value of λ and μ so how can you say "different values" ? To what did you compare or check it?

The rest of your work is nice. :smile:
 
ahh yes. I should say:
With the values of λ and μ the coefficients of K become:
LHS=3-3(3)=-6
RHS=-6+2=-4
LHS≠RHS, and so the lines are skew. I'm not sure how I would compare of check this?
 
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If I don't misinterpret your post, the value of λ and μ should not be the same for the line to be skew. Check it using the third equation, comparing the k components. You'll end up LHS is not the same as RHS.
 
yes. Thank you songoku. The values are different and so the lines are skew.
 
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