Andrew Mason
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Two gases with different specific heats will have two different temperatures when placed in the same blackbody radiation field.SpaceTiger said:One could just as easily say that the temperature of a gas is the same as that it would obtain in a certain blackbody radiation field. The argument is completely symmetric.
What is your definition of thermodynamic equilibrium as it applies to pure radiation?For any system, temperature is only well-defined in equilibrium. A laser would not be said to be in thermodynamic equilibrium, so it wouldn't have a temperature.
The laser source will reach a stable temperature and emit a blackbody spectrum typical of that temperature. It will also emit a swack of identical photons whose frequency depends on the energy level of the excited electrons in the laser material. If blackbody radiation has a temperature, why don't the laser photons?
As Chronos points out, the definition of temperature is somewhat elusive.
AM