(adsbygoogle = window.adsbygoogle || []).push({}); [SOLVED] Dynamics Question

1. The problem statement, all variables and given/known data

A skier on a slope inclined at 4.7(degrees) to the horizontal pushes on ski poles and starts down the slope. The initial speed is 2.7m/s. The coefficient of kinetic friction between skis and snow is 0.11. Determine how far the skier will slide before coming to rest.

2. Relevant equations

Fnet=ma

Fg=mg

v2=v1+2ad

Ff(force of friction)=uk(coefficiant of kinetic friction)xFn(normal force)

3. The attempt at a solution

Well after drawing a free body diagram, I concluded that Fnet=fg+fappcos4.7-(force of friction) after subbing in:

ma=mg+fappcos4.7-uk(Fn)

mass cancels out so:

a=g+fappcos4.7-uk(Fn)

but now I have no fapp value. I also tried solving it without a Fapp and subbing my acceleration answer into the relevant equation to get the distance, but my answer was wayyyyy of the right answer, which is 13m

I wish I could explain more or show that I tired more, but these type of questions always confuse me, I've yet to solve one.

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# Homework Help: Dynamics Question

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