Effect of TIME on SPECIFIC HEAT?

AI Thread Summary
The experiment involved using a calorimeter to determine the specific heat of an unknown metal by measuring the initial and final temperatures after adding the metal to water. The time taken to reach equilibrium is significant as it can provide insights into the heat transfer efficiency and thermal properties of the materials involved. To visualize the data, plotting temperature variation against time is recommended, which can illustrate how quickly the system reaches thermal equilibrium. This graph can help in analyzing the cooling or heating rates of the substances. Understanding these dynamics is crucial for deeper insights into thermal interactions in calorimetry.
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We did an experiment using a calorimeter in class, where we dropped a hot piece of metal into water in the calorimeter. We measured initial temp of metal + water, and the final equilibrium temperature. This allowed us to calculated the specific heat of the unknown metal (we also had the mass etc).


However, we also were asked to measure the TIME taken to reach equilibrium after the metal was added to the water, but why? What significance does the time to reach equilibrium have?

Thanks!
 
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What graphs should I draw?

We did an experiment using a calorimeter in class, where we dropped a hot piece of metal into water in the calorimeter. We measured initial temp of metal + water, and the final equilibrium temperature. This allowed us to calculated the specific heat of the unknown metal (we also had the mass etc). We also measured the time taken to reach equilibrium temperature.

What graphs should I plot though? We were told to plot graphs but I've got no idea what to plot.

Thanks!
 


you may plot temperature variation with time!
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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