- #1
jena
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Hi,
My problem is:
An electron( mass m=9.11 x 10^-31 kg) is accelerated in the uniform field E( E=1.45 x 10^4 N/C) between two parallel charged plates. The separation of the plates is 1.10 cm. The electron is accelerated from rest near the negative plate and passes through a tiny hole in the positive plate. With what speed does it leave the hole?
Work
m=9.11 x 10^-31 kg
E=1.45 x 10^4 N/C
distance= 1.10 x 10^.2 m
q= -1.6 x 10^-19 C
qE(s) = ½ mv^2 - ½ mv^2
-1.6 x 10^-19 C= ½ (9.0 x 10^-31 kg)(v)^2
solve for v
v=7.14 x10^-7 m/s
Is this the correct way of approaching the problem, or answer?
Please help
Thank You
My problem is:
An electron( mass m=9.11 x 10^-31 kg) is accelerated in the uniform field E( E=1.45 x 10^4 N/C) between two parallel charged plates. The separation of the plates is 1.10 cm. The electron is accelerated from rest near the negative plate and passes through a tiny hole in the positive plate. With what speed does it leave the hole?
Work
m=9.11 x 10^-31 kg
E=1.45 x 10^4 N/C
distance= 1.10 x 10^.2 m
q= -1.6 x 10^-19 C
qE(s) = ½ mv^2 - ½ mv^2
-1.6 x 10^-19 C= ½ (9.0 x 10^-31 kg)(v)^2
solve for v
v=7.14 x10^-7 m/s
Is this the correct way of approaching the problem, or answer?
Please help
Thank You
Last edited: