Electric field in special relativity

AI Thread Summary
A charge q at rest in frame O generates an electric field E' in frame O' moving with velocity βc. The electric field is expressed as E'=γ*q*(x',y',z')/(4πεo*γ²(x'²+y'²+z'²)3/2). The challenge is to demonstrate that E' can also be represented as E'=q*r'/(4πεo*γ²*r'²(1-βsin²θ)*r'). The user is struggling to manipulate the equation to derive the desired formula, particularly in relating sinθ to the components of r'. The discussion concludes with the user indicating that the problem has been resolved.
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Hello,

Homework Statement



A charge q is at rest in frame O. In O' with velocity βc in x direction, at t'=0 the charge is at the origine O' and produce an electric field E' at position r'=(x',y',z') :
E'=γ*q*(x',y',z')/(4πεo*γ²(x'²+y'²+z'²)3/2)
If θ is the angle between r' and x, show that:
E'=q*r'/(4πεo*γ²*r'²(1-βsin²θ)*r')


Homework Equations





The Attempt at a Solution


I'm blocking at this step :
E'=q*r'/(4πεo*γ²*(x'²+(y'²+z'²)/γ²)^3/2)
sinθ=y'/r' but I can't find a way to find the asked formula, I think that there's something that I'm missing but don't know what.
Thanks
 
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