Electric field intensity with a charge decreasing over time

Click For Summary
SUMMARY

The discussion focuses on deriving the electric field intensity (E) inside and outside a lossy dielectric sphere with a time-varying charge distribution. The initial charge distribution is uniform, and the relationship σ∇E = dp/dt is established, where p represents the volume density. The participant aims to express E in terms of time (t) by applying spherical coordinates and integrating over the radial distance (r). Further clarification on the term dp/dt is suggested to enhance the formulation.

PREREQUISITES
  • Understanding of electric field concepts in electromagnetism
  • Familiarity with lossy dielectric materials
  • Knowledge of spherical coordinates in vector calculus
  • Basic principles of charge density and its time dependence
NEXT STEPS
  • Research the mathematical derivation of electric fields in lossy dielectrics
  • Study the application of spherical coordinates in electromagnetism
  • Explore the implications of time-varying charge distributions on electric fields
  • Learn about the physical significance of the divergence operator in vector fields
USEFUL FOR

Physicists, electrical engineers, and students studying electromagnetism, particularly those interested in the behavior of electric fields in lossy dielectric materials.

ForTheGreater
Messages
22
Reaction score
0
So a lossy dielectric sphere gets an initial charge distribution evenly across the sphere.

Find an expression for E inside and outside the sphere for all t.



I figured that σ∇E=dp/dt
p being volume denity.

So I apply spherical coordinates to the div of E and integrate over r to get an expression for E. But I need to do something with the dp/dt since I want t in the expression.
 
Physics news on Phys.org
Hello For,

Perhaps you have a better chance to get some assistance if you formulate a bit more completely using the template. Lossy ? ## \sigma ## <--> dp/dt ?
 

Similar threads

Replies
23
Views
5K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
14
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
9
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
4
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
4
Views
1K