Electric Field of a finite line of charge

AI Thread Summary
To calculate the electric field at point P due to a finite line of charge, the initial assumption that the electric field is zero is incorrect, as this only applies to an infinite line of charge. The appropriate method involves dividing the finite line of charge into small segments, each contributing to the electric field at point P. By integrating the contributions from all these segments, the total electric field can be determined. The equation provided for the perpendicular bisector does not apply in this case, necessitating a different approach. Understanding the principles of superposition and integration is crucial for solving this problem effectively.
johnnyies
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Homework Statement


I just took an exam and one of the questions gave us a finite line of charge and asked us to calculate the E-field at a point at a point P to the right of the line of charge.

here is a poor sketch

[+][+][+][+][+][+][+][+][+][+][+][+]---------------------------------- .P
(thin line of charge)

now my initial thought would be that E at point P = 0, since if we drew the field lines they would point radially outward and perpendicular to the line of charge. However, 0 was not any of the available answers.

The only equation given to us was the one for a point that is in the perpendicular bisector of the line of charge, which cannot apply in this case. How would we go about solving this?

Homework Equations


The Attempt at a Solution

 
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You wrote,

"now my initial thought would be that E at point P = 0, since if we drew the field lines they would point radially outward and perpendicular to the line of charge. However, 0 was not any of the available."

I think that is true only for an infinite line of charge. I think you could divide the line of charge into small elements and add the electric field at point P due to all the elements of charge?
 
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