Electric Fields and Potential Difference. Combining Formulae

[Yer Madder]

Determine how far apart two parallel plates must be situated so that a potential difference of 2.50*10^2 V produces an electric field strength of 2.00*10^3 N/C



F=(k*Q1*Q2)/r^2
PD=kQ/r
E=kQ/r^2



I cannot even figure out which formulae to combine...

 

[gneill]

Determine how far apart two parallel plates must be situated so that a potential difference of 2.50*10^2 V produces an electric field strength of 2.00*10^3 N/C



F=(k*Q1*Q2)/r^2
PD=kQ/r
E=kQ/r^2



I cannot even figure out which formulae to combine...

You should remember that electric field strength can be measured in units N/C or V/m; they are equivalent sets of units.