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Electric Fields and Potential Difference. Combining Formulae

  1. Jan 21, 2012 #1
    Determine how far apart two parallel plates must be situated so that a potential difference of 2.50*10^2 V produces an electric field strength of 2.00*10^3 N/C



    F=(k*Q1*Q2)/r^2
    PD=kQ/r
    E=kQ/r^2




    I cannot even figure out which formulae to combine...
     
  2. jcsd
  3. Jan 21, 2012 #2

    gneill

    User Avatar

    Staff: Mentor

    You should remember that electric field strength can be measured in units N/C or V/m; they are equivalent sets of units.
     
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